x+1/x=2 হলে, x^7+1/x^7 = কত?

প্রশ্ন

x + \dfrac{1}{x}=2

হলে, x^7+\dfrac{1}{x^7} = ?

উত্তর

2

সমাধান

প্রশ্নানুসারে, x + \dfrac{1}{x}=2

\Rightarrow \dfrac{x^2+1}{x} = 2

\Rightarrow x^2 + 1 = 2x

\Rightarrow x^2 -2x + 1=0

\Rightarrow x^2 - x -x +1 = 0

\Rightarrow x(x-1) -1(x-1) = 0

\Rightarrow (x-1)(x-1) = 0

\therefore x - 1 = 0
\Rightarrow x = 1

এখন, x^7 + \dfrac{1}{x^7}
= 1^7 + \dfrac{1}{1^7}
= 1 + 1
= 2

\therefore x^7 + \dfrac{1}{x^7} = 2 \text{(Answer)}

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